यदि \(A={x:x\) (16) का धनात्मक भाजक है और (x) सम है(}) तो कौन सा समुच्चय (A) के बराबर है?
If \(A={x:x\) is a positive divisor of (16) and (x) is even(}) then which set is equal to (A)?
Explanation opens after your attempt
Correct Answer
A. ({2,4,8,16})
Concept
The even positive divisors of (16) are (2,4,8,16). First list all divisors and then apply the condition.
Why this answer is correct
The correct answer is A. ({2,4,8,16}). The even positive divisors of (16) are (2,4,8,16). First list all divisors and then apply the condition.
Exam Tip
(16) के सम धनात्मक भाजक (2,4,8,16) हैं। पहले सभी भाजक लिखें फिर शर्त लगाएं।
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