यदि \(A={x:x\in\mathbb{N},x\le4}\) और \(B={y:y\in\mathbb{N},y<3}\) हैं, तो (n\(A\times B\)) कितना है?
If \(A={x:x\in\mathbb{N},x\le4}\) and \(B={y:y\in\mathbb{N},y<3}\), what is (n\(A\times B\))?
Explanation opens after your attempt
Correct Answer
A. (8)
Concept
\(A=\{1,2,3,4\}\) and \(B=\{1,2\}\), so (n\(A\times B\)=4\times2=8). Convert set-builder form into roster form first.
Why this answer is correct
The correct answer is A. (8). \(A=\{1,2,3,4\}\) and \(B=\{1,2\}\), so (n\(A\times B\)=4\times2=8). Convert set-builder form into roster form first.
Exam Tip
\(A=\{1,2,3,4\}\) और \(B=\{1,2\}\), इसलिए (n\(A\times B\)=4\times2=8)। सेट-बिल्डर रूप को पहले सूची रूप में बदलें।
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