यदि \(A=\{1,2,3\}\), \(B=\{2,3,4\}\) और \(C=\{3,4,5\}\) हैं, तो (A\times\(B\cap C\)) में कितने अवयव होंगे?
If \(A=\{1,2,3\}\), \(B=\{2,3,4\}\) and \(C=\{3,4,5\}\), how many elements are in (A\times\(B\cap C\))?
Explanation opens after your attempt
A. (6)
Concept
\(B\cap C={3,4}\), so (n(A\times\(B\cap C\))=3\times2=6). Find the intersection before counting the Cartesian product.
Why this answer is correct
The correct answer is A. (6). \(B\cap C={3,4}\), so (n(A\times\(B\cap C\))=3\times2=6). Find the intersection before counting the Cartesian product.
Exam Tip
\(B\cap C={3,4}\), इसलिए (n(A\times\(B\cap C\))=3\times2=6)। प्रतिच्छेद निकालकर ही कार्तीय गुणन गिनें।
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