यदि \(A=\{1,2,3,4\}\), तो (\mathcal{P}(A)) में ऐसे कितने उपसमुच्चय हैं जिनका पूरक (A) के सापेक्ष स्वयं के बराबर है?

If \(A=\{1,2,3,4\}\), how many subsets in (\mathcal{P}(A)) are equal to their own complement with respect to (A)?

Explanation opens after your attempt
Correct Answer

A. (0)

Step 1

Concept

No set can be equal to its complement because each element would have to be both included and not included. Therefore the count is (0).

Step 2

Why this answer is correct

The correct answer is A. (0). No set can be equal to its complement because each element would have to be both included and not included. Therefore the count is (0).

Step 3

Exam Tip

कोई समुच्चय अपने पूरक के बराबर नहीं हो सकता क्योंकि तब वह अपने ही प्रत्येक तत्व को रखेगा और नहीं भी रखेगा। इसलिए संख्या (0) है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(A=\{1,2,3,4\}\), तो (\mathcal{P}(A)) में ऐसे कितने उपसमुच्चय हैं जिनका पूरक (A) के सापेक्ष स्वयं के बराबर है? / If \(A=\{1,2,3,4\}\), how many subsets in (\mathcal{P}(A)) are equal to their own complement with respect to (A)?

Correct Answer: A. (0). Explanation: कोई समुच्चय अपने पूरक के बराबर नहीं हो सकता क्योंकि तब वह अपने ही प्रत्येक तत्व को रखेगा और नहीं भी रखेगा। इसलिए संख्या (0) है। / No set can be equal to its complement because each element would have to be both included and not included. Therefore the count is (0).

Which concept should I revise for this Mathematics MCQ?

No set can be equal to its complement because each element would have to be both included and not included. Therefore the count is (0).

What exam hint can help solve this Mathematics question?

कोई समुच्चय अपने पूरक के बराबर नहीं हो सकता क्योंकि तब वह अपने ही प्रत्येक तत्व को रखेगा और नहीं भी रखेगा। इसलिए संख्या (0) है।