यदि \(A=\{1,2,3,4,5\}\), तो (\mathcal{P}(A)) के कितने तत्वों में (1) होगा, (2) नहीं होगा और ठीक (3) तत्व होंगे?
If \(A=\{1,2,3,4,5\}\), how many elements of (\mathcal{P}(A)) contain (1), do not contain (2), and have exactly (3) elements?
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Correct Answer
B. (3)
Concept
(1) is fixed and (2) is excluded, so choose (2) elements from (3,4,5). The count is \(\binom{3}{2}=3\).
Why this answer is correct
The correct answer is B. (3). (1) is fixed and (2) is excluded, so choose (2) elements from (3,4,5). The count is \(\binom{3}{2}=3\).
Exam Tip
(1) निश्चित है और (2) नहीं लेना है, इसलिए (3,4,5) में से (2) तत्व चुनने होंगे। संख्या \(\binom{3}{2}=3\) है।
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