यदि \(A=\{-1,0,1\}\) और \(B=\{0,1\}\) हैं, तो \(A\times B\) में कितने युग्म ((x,y)) ऐसे हैं जिनके लिए \(x^2=y\) है?
If \(A=\{-1,0,1\}\) and \(B=\{0,1\}\), how many pairs ((x,y)) in \(A\times B\) satisfy \(x^2=y\)?
Explanation opens after your attempt
Correct Answer
B. (3)
Concept
((-1)2=1), \(0^2=0\), and \(1^2=1\), so there are (3) pairs. Check (y) for each (x).
Why this answer is correct
The correct answer is B. (3). ((-1)2=1), \(0^2=0\), and \(1^2=1\), so there are (3) pairs. Check (y) for each (x).
Exam Tip
((-1)2=1), \(0^2=0\), और \(1^2=1\), इसलिए (3) युग्म मिलते हैं। प्रत्येक (x) के लिए (y) जाँचें।
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