शब्द संभावना के अक्षरों की अलग व्यवस्थाएं कितनी होंगी?
How many distinct arrangements can be made from the letters of SAMBHAVNA?
Explanation opens after your attempt
A. (181440)
Concept
There are (9) letters with two different letters repeated twice, so \(\frac{9!}{2!2!}=90720\). In exams, accurate repeated-letter counting is essential.
Why this answer is correct
The correct answer is A. (181440). There are (9) letters with two different letters repeated twice, so \(\frac{9!}{2!2!}=90720\). In exams, accurate repeated-letter counting is essential.
Exam Tip
(9) अक्षरों में (2) अक्षर दो-दो बार आते हैं, इसलिए \(\frac{9!}{2!2!}=90720\); सही गणना में repeated letters को ठीक गिनना जरूरी है।
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