शब्द (ENGINEERING) के अक्षरों की अलग-अलग व्यवस्थाएं कितनी होंगी?
How many distinct arrangements are possible using the letters of (ENGINEERING)?
Explanation opens after your attempt
Correct Answer
A. (277200)
Concept
There are (11) letters with (E) three times, (N) three times, (G) twice and (I) twice. The number is \(\frac{11!}{3!3!2!2!}=277200\).
Why this answer is correct
The correct answer is A. (277200). There are (11) letters with (E) three times, (N) three times, (G) twice and (I) twice. The number is \(\frac{11!}{3!3!2!2!}=277200\).
Exam Tip
(11) अक्षरों में (E) तीन, (N) तीन, (G) दो और (I) दो बार हैं। संख्या \(\frac{11!}{3!3!2!2!}=277200\) है।
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