शब्द (COMMITTEE) के अक्षरों की अलग-अलग व्यवस्थाएं कितनी होंगी?
How many distinct arrangements are possible using the letters of (COMMITTEE)?
Explanation opens after your attempt
Correct Answer
A. (45360)
Concept
There are (9) letters with (M,T,E) each repeated twice, so \(\frac{9!}{2!2!2!}=45360\). In exams, put each repeated letter factorial in the denominator.
Why this answer is correct
The correct answer is A. (45360). There are (9) letters with (M,T,E) each repeated twice, so \(\frac{9!}{2!2!2!}=45360\). In exams, put each repeated letter factorial in the denominator.
Exam Tip
(9) अक्षरों में (M,T,E) दो-दो बार हैं, इसलिए \(\frac{9!}{2!2!2!}=45360\)। परीक्षा में हर repeated letter का factorial हर में रखें।
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