शब्द (ALGEBRA) के अक्षरों की अलग-अलग व्यवस्थाएं कितनी होंगी?
How many distinct arrangements are possible using the letters of (ALGEBRA)?
Explanation opens after your attempt
Correct Answer
C. (2520)
Concept
There are (7) letters with (A) repeated twice, so \(\frac{7!}{2!}=2520\). In exams, divide by repeated letters.
Why this answer is correct
The correct answer is C. (2520). There are (7) letters with (A) repeated twice, so \(\frac{7!}{2!}=2520\). In exams, divide by repeated letters.
Exam Tip
(7) अक्षरों में (A) दो बार है, इसलिए \(\frac{7!}{2!}=2520\)। परीक्षा में repeated letters से भाग देना जरूरी है।
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