फलन (f(x)=\sqrt{x-2-16}) का प्रांत ज्ञात कीजिए।
Find the domain of (f(x)=\sqrt{x-2-16}).
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-4]\cup[4,\infty\))
Concept
For the square root \(x^2-16\ge 0\), so \(x^2\ge 16\). Hence \(x\le -4\) or \(x\ge 4\).
Why this answer is correct
The correct answer is A. (\(-\infty,-4]\cup[4,\infty\)). For the square root \(x^2-16\ge 0\), so \(x^2\ge 16\). Hence \(x\le -4\) or \(x\ge 4\).
Exam Tip
वर्गमूल के लिए \(x^2-16\ge 0\), इसलिए \(x^2\ge 16\)। अतः \(x\le -4\) या \(x\ge 4\)।
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