शब्द अनुप्रयोग के (9) अक्षरों में दो-दो अक्षर समान हैं। अलग व्यवस्थाएं कितनी होंगी?

A word has (9) letters with two different letters each repeated (2) times. How many distinct arrangements are possible?

Explanation opens after your attempt
Correct Answer

B. (90720)

Step 1

Concept

Two groups are repeated (2) times each, so the number is \(\frac{9!}{2!2!}=90720\). In exams, put each repeated group factorial in the denominator.

Step 2

Why this answer is correct

The correct answer is B. (90720). Two groups are repeated (2) times each, so the number is \(\frac{9!}{2!2!}=90720\). In exams, put each repeated group factorial in the denominator.

Step 3

Exam Tip

दो समूह (2) बार समान हैं, इसलिए संख्या \(\frac{9!}{2!2!}=90720\) है। परीक्षा में हर repeated group का factorial हर में रखें।

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शब्द अनुप्रयोग के (9) अक्षरों में दो-दो अक्षर समान हैं। अलग व्यवस्थाएं कितनी होंगी? / A word has (9) letters with two different letters each repeated (2) times. How many distinct arrangements are possible?

Correct Answer: B. (90720). Explanation: दो समूह (2) बार समान हैं, इसलिए संख्या \(\frac{9!}{2!2!}=90720\) है। परीक्षा में हर repeated group का factorial हर में रखें। / Two groups are repeated (2) times each, so the number is \(\frac{9!}{2!2!}=90720\). In exams, put each repeated group factorial in the denominator.

Which concept should I revise for this Mathematics MCQ?

Two groups are repeated (2) times each, so the number is \(\frac{9!}{2!2!}=90720\). In exams, put each repeated group factorial in the denominator.

What exam hint can help solve this Mathematics question?

दो समूह (2) बार समान हैं, इसलिए संख्या \(\frac{9!}{2!2!}=90720\) है। परीक्षा में हर repeated group का factorial हर में रखें।