शब्द अनुप्रयोग के (9) अक्षरों में दो-दो अक्षर समान हैं। अलग व्यवस्थाएं कितनी होंगी?
A word has (9) letters with two different letters each repeated (2) times. How many distinct arrangements are possible?
Explanation opens after your attempt
B. (90720)
Concept
Two groups are repeated (2) times each, so the number is \(\frac{9!}{2!2!}=90720\). In exams, put each repeated group factorial in the denominator.
Why this answer is correct
The correct answer is B. (90720). Two groups are repeated (2) times each, so the number is \(\frac{9!}{2!2!}=90720\). In exams, put each repeated group factorial in the denominator.
Exam Tip
दो समूह (2) बार समान हैं, इसलिए संख्या \(\frac{9!}{2!2!}=90720\) है। परीक्षा में हर repeated group का factorial हर में रखें।
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