यदि \(U={x:x\in\mathbb{Z},-10\le x\le 10}\) और \(A={x:x^2-9x+20\le 0}\), तो (A') क्या है?
If \(U={x:x\in\mathbb{Z},-10\le x\le 10}\) and \(A={x:x^2-9x+20\le 0}\), what is (A')?
Explanation opens after your attempt
A. ({-10,-9,-8,-7,-6,-5,-4,-3,-2,-1,0,1,2,3,7,8,9,10})
Simple Explanation
\(x^2-9x+20\le 0\Rightarrow 4\le x\le 5\) नहीं, सही हल \(4\le x\le 5\) है, इसलिए \(A=\{4,5\}\)। दिए गए विकल्पों में (A') वही है जो (U) से (4,5) हटाकर बनता है। / \(x^2-9x+20\le 0\Rightarrow 4\le x\le 5\), so \(A=\{4,5\}\). The complement is obtained by removing (4,5) from (U).
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