If \(x\) is real and both \(x\ge -6\) and \(x<1\) apply on the number line, what is the correct interval?

Correct answer: \([-6,1)\)

We need values that satisfy both inequalities simultaneously. Since \(x\ge -6\), \(-6\) is included; since \(x<1\), \(1\) is excluded. Hence, the common interval is \([-6,1)\). Option \((-6,1]\) reverses the endpoint inclusion. Exam tip: use a square bracket for \(\ge\) or \(\le\), and a round bracket for \(<\) or \(>\).