Which is the correct interval on the number line for (|4x+1|\le 9)?असमानता (|4x+1|\le 9) का संख्या रेखा पर सही interval कौन-सा है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: ([-\frac{5}{2},2])([-\frac{5}{2},2])
(-9\le4x+1\le9) gives (-10\le4x\le8), so (-\frac{5}{2}\le x\le2). In exams, modulus with (\le) gives a closed interval.(-9\le4x+1\le9) से (-10\le4x\le8), इसलिए (-\frac{5}{2}\le x\le2)। परीक्षा में (\le) वाले modulus में closed interval लें।
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