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After removing (0) from the interval ([-3,7]), which form appears on the number line?

Answer and explanation

Correct answer: \([-3,0)\cup(0,7]\)

The original interval includes both \(-3\) and \(7\). Removing only \(0\) creates an open point at \(0\), while \(-3\) and \(7\) remain included. Hence, the set is \([-3,0)\cup(0,7]\). In option B, \(0\) is still included, while option C incorrectly excludes \(-3\) and \(7\) as well. Exam tip: When a point is removed from an interval, use an open parenthesis at that point.

Related tags

Linear InequalitiesInterval NotationSet DifferenceNumber LineUnion Of IntervalsRepresentation On Number LineMathematicsClass 11 Mcq

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