Which statement is the negation of \(x<-2\)?

Correct answer: \(x\ge -2\)

The negation of \(x<-2\) includes every value that is not less than \(-2\), so it is \(x\ge -2\). Equality must be included when negating a strict inequality. Option C is incorrect because it includes values less than or equal to \(-2\), rather than the values outside \(x<-2\). Exam tip: the negation of \(x<a\) is \(x\ge a\), while the negation of \(x>a\) is \(x\le a\).