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If (x\in \mathbb{Z}) and ( \frac{x+2}{3}>1 ) and (x<9), how many integer solutions are there?यदि (x\in \mathbb{Z}) और ( \frac{x+2}{3}>1 ) तथा (x<9), तो कितने पूर्णांक हल हैं?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (5)(5)
The first condition gives (x>1) and the second gives (x<9), so (x=2,3,4,5,6,7,8), which are (7) integers. Always list integer endpoints carefully.पहली शर्त से (x>1) और दूसरी से (x<9) है इसलिए (x=2,3,4,5,6,7,8) कुल (7) नहीं बल्कि विकल्प जांचने पर (7) होना चाहिए।
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