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If (x) is a real number, what is the solution of (x^2+1>0)?यदि (x) एक वास्तविक संख्या है, तो (x^2+1>0) का हल क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: All (x\in \mathbb{R})सभी (x\in \mathbb{R})
Since (x^2\geq 0), (x^2+1\geq 1>0) for all real (x). Recognizing always positive forms is useful.क्योंकि (x^2\geq 0), इसलिए (x^2+1\geq 1>0) सभी वास्तविक (x) के लिए सत्य है। धनात्मक निश्चित रूप पहचानना उपयोगी है।
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