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Subjects
Class 11MathematicsLinear InequalitiesIntroduction to inequalitiesHard
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If (x\in \mathbb{Z}) and (-5\leq 2x-1<9), how many integer solutions are there?

Answer and explanation

Correct answer: (7)

(-4\leq 2x<10) gives (-2\leq x<5), so (-2,-1,0,1,2,3,4) are (7) solutions. Check endpoints separately.

Related tags

Integer SolutionsCompound InequalityCountingIntroduction To InequalitiesLinear InequalitiesMathematicsClass 11 Mcq
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10 more MCQs
  1. 1What does a < b mean?
  2. 2What is the correct meaning of the inequality \(x\ge 7\)?
  3. 3Which of the following is a linear inequality?
  4. 4Which of the following values satisfies the inequality \(x<4\)?
  5. 5For x=2, how is the statement x≤2?
  6. 6How should the statement “y is more than 10” be written as an inequality?
  7. 7Which inequality represents the statement “the variable p is not more than 12”?
  8. 8If (x>3), what do we get after adding (2) to both sides?
  9. 9If (m<6), what happens after multiplying both sides by (4)?
  10. 10If x>5, which inequality is correct after multiplying both sides by −1?
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