\(^{n}P_r\) में (r>n) होने पर गिनती (0) क्यों होती है?
Why is the count (0) in \(^{n}P_r\) when (r>n)?
Explanation opens after your attempt
B. क्योंकि बिना पुनरावृत्ति (n) से अधिक स्थान नहीं भरे जा सकतेBecause more than (n) positions cannot be filled without repetition
Concept
Without repetition more than (n) positions cannot be filled using (n) distinct objects. In exams check the availability condition first.
Why this answer is correct
The correct answer is B. क्योंकि बिना पुनरावृत्ति (n) से अधिक स्थान नहीं भरे जा सकते / Because more than (n) positions cannot be filled without repetition. Without repetition more than (n) positions cannot be filled using (n) distinct objects. In exams check the availability condition first.
Exam Tip
बिना पुनरावृत्ति (n) अलग वस्तुओं से अधिक positions नहीं भरी जा सकतीं। परीक्षा में availability condition पहले जाँचें।
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