कौन सा कथन \(x^2\le 0\) को वास्तविक संख्याओं में सही ढंग से हल करता है?

Which statement correctly solves \(x^2\le 0\) over real numbers?

Explanation opens after your attempt
Correct Answer

A. (x=0)

Step 1

Concept

For every real (x), \(x^2\ge 0\), so \(x^2\le 0\) is possible only when \(x^2=0\). Hence (x=0) is the only solution.

Step 2

Why this answer is correct

The correct answer is A. (x=0). For every real (x), \(x^2\ge 0\), so \(x^2\le 0\) is possible only when \(x^2=0\). Hence (x=0) is the only solution.

Step 3

Exam Tip

हर वास्तविक (x) के लिए \(x^2\ge 0\), इसलिए \(x^2\le 0\) तभी होगा जब \(x^2=0\)। अतः (x=0) ही हल है।

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Mathematics Answer, Explanation and Revision Hints

कौन सा कथन \(x^2\le 0\) को वास्तविक संख्याओं में सही ढंग से हल करता है? / Which statement correctly solves \(x^2\le 0\) over real numbers?

Correct Answer: A. (x=0). Explanation: हर वास्तविक (x) के लिए \(x^2\ge 0\), इसलिए \(x^2\le 0\) तभी होगा जब \(x^2=0\)। अतः (x=0) ही हल है। / For every real (x), \(x^2\ge 0\), so \(x^2\le 0\) is possible only when \(x^2=0\). Hence (x=0) is the only solution.

Which concept should I revise for this Mathematics MCQ?

For every real (x), \(x^2\ge 0\), so \(x^2\le 0\) is possible only when \(x^2=0\). Hence (x=0) is the only solution.

What exam hint can help solve this Mathematics question?

हर वास्तविक (x) के लिए \(x^2\ge 0\), इसलिए \(x^2\le 0\) तभी होगा जब \(x^2=0\)। अतः (x=0) ही हल है।