कौन सा कथन \(x^2\le 0\) को वास्तविक संख्याओं में सही ढंग से हल करता है?
Which statement correctly solves \(x^2\le 0\) over real numbers?
Explanation opens after your attempt
A. (x=0)
Concept
For every real (x), \(x^2\ge 0\), so \(x^2\le 0\) is possible only when \(x^2=0\). Hence (x=0) is the only solution.
Why this answer is correct
The correct answer is A. (x=0). For every real (x), \(x^2\ge 0\), so \(x^2\le 0\) is possible only when \(x^2=0\). Hence (x=0) is the only solution.
Exam Tip
हर वास्तविक (x) के लिए \(x^2\ge 0\), इसलिए \(x^2\le 0\) तभी होगा जब \(x^2=0\)। अतः (x=0) ही हल है।
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