किस विकल्प में \(A=\{1,2,3,4\}\) से \(B=\{a,b,c\}\) में फलन नहीं है जबकि (A) का हर अवयव प्रथम घटक के रूप में मौजूद है?
Which option is not a function from \(A=\{1,2,3,4\}\) to \(B=\{a,b,c\}\) even though every element of (A) occurs as a first component?
Explanation opens after your attempt
Correct Answer
C. ({(1,b),(2,c),(3,a),(4,b),(3,c)})
Concept
In option (C), (3) has two images (a) and (c). A function requires both existence and uniqueness.
Why this answer is correct
The correct answer is C. ({(1,b),(2,c),(3,a),(4,b),(3,c)}). In option (C), (3) has two images (a) and (c). A function requires both existence and uniqueness.
Exam Tip
विकल्प (C) में (3) की दो छवियां (a) और (c) हैं। फलन के लिए पूर्णता के साथ अद्वितीयता भी जरूरी है।
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