असमानता \(\frac{7-x}{3}\leq 2\) का हल कौन सा है?
Which is the solution of \(\frac{7-x}{3}\leq 2\)?
Explanation opens after your attempt
B. \(x\geq 1\)
Concept
From \(7-x\leq 6\), we get \(-x\leq -1\). Dividing by (-1) gives \(x\geq 1\).
Why this answer is correct
The correct answer is B. \(x\geq 1\). From \(7-x\leq 6\), we get \(-x\leq -1\). Dividing by (-1) gives \(x\geq 1\).
Exam Tip
\(7-x\leq 6\) से \(-x\leq -1\) मिलता है। (-1) से भाग देने पर \(x\geq 1\) होता है।
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