असमानता \(\frac{x-10}{-4}\le 3\) का संख्या रेखा हल कौन-सा है?

Which is the number line solution of \(\frac{x-10}{-4}\le 3\)?

Explanation opens after your attempt
Correct Answer

B. \(x\ge-2\), (-2) पर बंद बिंदु और दाईं ओर\(x\ge-2\), closed dot at (-2) shaded right

Step 1

Concept

Multiplying by (-4) reverses the sign to \(x-10\ge-12\), so \(x\ge-2\). In exams, reverse the sign when removing a negative denominator.

Step 2

Why this answer is correct

The correct answer is B. \(x\ge-2\), (-2) पर बंद बिंदु और दाईं ओर / \(x\ge-2\), closed dot at (-2) shaded right. Multiplying by (-4) reverses the sign to \(x-10\ge-12\), so \(x\ge-2\). In exams, reverse the sign when removing a negative denominator.

Step 3

Exam Tip

(-4) से गुणा करने पर चिन्ह पलटकर \(x-10\ge-12\), इसलिए \(x\ge-2\)। परीक्षा में negative denominator हटाते समय sign reverse करें।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(\frac{x-10}{-4}\le 3\) का संख्या रेखा हल कौन-सा है? / Which is the number line solution of \(\frac{x-10}{-4}\le 3\)?

Correct Answer: B. \(x\ge-2\), (-2) पर बंद बिंदु और दाईं ओर / \(x\ge-2\), closed dot at (-2) shaded right. Explanation: (-4) से गुणा करने पर चिन्ह पलटकर \(x-10\ge-12\), इसलिए \(x\ge-2\)। परीक्षा में negative denominator हटाते समय sign reverse करें। / Multiplying by (-4) reverses the sign to \(x-10\ge-12\), so \(x\ge-2\). In exams, reverse the sign when removing a negative denominator.

Which concept should I revise for this Mathematics MCQ?

Multiplying by (-4) reverses the sign to \(x-10\ge-12\), so \(x\ge-2\). In exams, reverse the sign when removing a negative denominator.

What exam hint can help solve this Mathematics question?

(-4) से गुणा करने पर चिन्ह पलटकर \(x-10\ge-12\), इसलिए \(x\ge-2\)। परीक्षा में negative denominator हटाते समय sign reverse करें।