असमानता \(6\le \frac{13-2x}{3}<15\) का संख्या रेखा पर सही interval कौन-सा है?
Which is the correct interval on the number line for \(6\le \frac{13-2x}{3}<15\)?
Explanation opens after your attempt
Correct Answer
C. (\(-16,-\frac{5}{2}]\)
Concept
\(18\le13-2x<45\) gives \(5\le-2x<32\), so \(-16<x\le-\frac{5}{2}\). In exams, reverse order and signs when dividing by a negative.
Why this answer is correct
The correct answer is C. (\(-16,-\frac{5}{2}]\). \(18\le13-2x<45\) gives \(5\le-2x<32\), so \(-16<x\le-\frac{5}{2}\). In exams, reverse order and signs when dividing by a negative.
Exam Tip
\(18\le13-2x<45\) से \(5\le-2x<32\), इसलिए \(-16<x\le-\frac{5}{2}\)। परीक्षा में ऋणात्मक से भाग देने पर क्रम और चिन्ह बदलें।
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