असमानता \(2\le \frac{7-3x}{2}<11\) का संख्या रेखा पर सही अंतराल कौन-सा है?
Which is the correct interval on the number line for \(2\le \frac{7-3x}{2}<11\)?
Explanation opens after your attempt
Correct Answer
A. ((-5,1])
Concept
\(4\le7-3x<22\) gives \(-3\le-3x<15\), so \(-5<x\le1\). In exams, dividing by a negative changes both order and signs.
Why this answer is correct
The correct answer is A. ((-5,1]). \(4\le7-3x<22\) gives \(-3\le-3x<15\), so \(-5<x\le1\). In exams, dividing by a negative changes both order and signs.
Exam Tip
\(4\le7-3x<22\) से \(-3\le-3x<15\), इसलिए \(-5<x\le1\)। परीक्षा में ऋणात्मक से भाग देने पर क्रम और चिन्ह दोनों बदलते हैं।
Login to save your score, XP, coins and progress.