Class 11 Mathematics Linear Inequalities representation on number line Hard Level 48

असमानता \(2\le\frac{3x-1}{4}\le 5\) का संख्या रेखा पर सही interval कौन-सा है?

Which is the correct interval on the number line for \(2\le\frac{3x-1}{4}\le 5\)?

Explanation opens after your attempt
Correct Answer

A. ([3,7])

Step 1

Concept

\(8\le3x-1\le20\) gives \(9\le3x\le21\), so \(3\le x\le7\). In exams, a closed compound inequality gives a closed interval.

Step 2

Why this answer is correct

The correct answer is A. ([3,7]). \(8\le3x-1\le20\) gives \(9\le3x\le21\), so \(3\le x\le7\). In exams, a closed compound inequality gives a closed interval.

Step 3

Exam Tip

\(8\le3x-1\le20\) से \(9\le3x\le21\), इसलिए \(3\le x\le7\)। परीक्षा में closed compound inequality से closed interval मिलता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

Check out these related questions:

  1. यदि \(\theta\) चतुर्थ चतुर्थांश में है और \(\cos \theta=\frac{8}{17}\), तो \(\tan \theta\) क्या होगा?
  2. यदि \(\sin x+\sin^2 x=0\), तो \(0\leq x<2\pi\) में कितने हल हैं?
  3. फलन (f(x)=\sin 2x+\sin 4x) का मूल आवर्त क्या है?
  4. \(5\sin x-12\cos x\) का अधिकतम मान क्या है?
  5. यदि \(\cos x=-\frac{1}{2}\), तो \(0\leq x<2\pi\) में (x) के मान कौन-से हैं?
  6. यदि \(\sin x=\frac{1}{2}\), तो \(0\leq x<2\pi\) में (x) के मान कौन-से हैं?
  7. \(\cos 3x\) का सही विस्तार कौन-सा है?
  8. \(\sin 3x\) का सही विस्तार कौन-सा है?
  9. यदि (x) तृतीय चतुर्थांश में है और \(\tan x=\frac{4}{3}\), तो \(\sin x\) क्या है?
  10. यदि (x) द्वितीय चतुर्थांश में है और \(\sin x=\frac{5}{13}\), तो \(\cos x\) क्या होगा?

Related Mathematics Learning Links

Mathematics Subject

Level-wise subject practice

Linear Inequalities Quiz

Chapter-wise MCQ practice

Search Similar MCQs

Find related questions

Daily Challenge

Fresh quiz practice
FAQs

Mathematics Answer, Explanation and Revision Hints

असमानता \(2\le\frac{3x-1}{4}\le 5\) का संख्या रेखा पर सही interval कौन-सा है? / Which is the correct interval on the number line for \(2\le\frac{3x-1}{4}\le 5\)?

Correct Answer: A. ([3,7]). Explanation: \(8\le3x-1\le20\) से \(9\le3x\le21\), इसलिए \(3\le x\le7\)। परीक्षा में closed compound inequality से closed interval मिलता है। / \(8\le3x-1\le20\) gives \(9\le3x\le21\), so \(3\le x\le7\). In exams, a closed compound inequality gives a closed interval.

Which concept should I revise for this Mathematics MCQ?

\(8\le3x-1\le20\) gives \(9\le3x\le21\), so \(3\le x\le7\). In exams, a closed compound inequality gives a closed interval.

What exam hint can help solve this Mathematics question?

\(8\le3x-1\le20\) से \(9\le3x\le21\), इसलिए \(3\le x\le7\)। परीक्षा में closed compound inequality से closed interval मिलता है।