असमानता \(1\le\frac{2x+3}{5}\le 3\) का संख्या रेखा पर सही अंतराल कौन-सा है?
Which is the correct interval on the number line for \(1\le\frac{2x+3}{5}\le 3\)?
Explanation opens after your attempt
Correct Answer
A. ([1,6])
Concept
\(5\le2x+3\le15\) gives \(2\le2x\le12\), so \(1\le x\le6\). In exams, a closed compound inequality gives a closed interval.
Why this answer is correct
The correct answer is A. ([1,6]). \(5\le2x+3\le15\) gives \(2\le2x\le12\), so \(1\le x\le6\). In exams, a closed compound inequality gives a closed interval.
Exam Tip
\(5\le2x+3\le15\) से \(2\le2x\le12\), इसलिए \(1\le x\le6\)। परीक्षा में बंद संयुक्त असमानता से बंद interval मिलता है।
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