असमानता \(|2x-1|\ge 7\) संख्या रेखा पर किस interval से दर्शाई जाएगी?
Which interval represents \(|2x-1|\ge 7\) on the number line?
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-3]\cup[4,\infty\))
Concept
\(|2x-1|\ge 7\) gives \(2x-1\le -7\) or \(2x-1\ge 7\), so \(x\le -3\) or \(x\ge 4\). In exams, absolute value with \(\ge\) forms closed outer rays.
Why this answer is correct
The correct answer is A. (\(-\infty,-3]\cup[4,\infty\)). \(|2x-1|\ge 7\) gives \(2x-1\le -7\) or \(2x-1\ge 7\), so \(x\le -3\) or \(x\ge 4\). In exams, absolute value with \(\ge\) forms closed outer rays.
Exam Tip
\(|2x-1|\ge 7\) से \(2x-1\le -7\) या \(2x-1\ge 7\), इसलिए \(x\le -3\) या \(x\ge 4\)। परीक्षा में \(\ge\) वाले absolute value में बाहर के closed rays बनते हैं।
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