किस फलन का डोमेन \(\mathbb{R}\setminus{-3,3}\) है?

Which function has domain \(\mathbb{R}\setminus{-3,3}\)?

Explanation opens after your attempt
Correct Answer

A. (f(x)=\frac{x}{x-2-9})

Step 1

Concept

In \(\frac{x}{x^2-9}\), the denominator is ((x-3)(x+3)), so \(x=\pm3\) are removed. In exams remove denominator zero values in rational functions.

Step 2

Why this answer is correct

The correct answer is A. (f(x)=\frac{x}{x-2-9}). In \(\frac{x}{x^2-9}\), the denominator is ((x-3)(x+3)), so \(x=\pm3\) are removed. In exams remove denominator zero values in rational functions.

Step 3

Exam Tip

\(\frac{x}{x^2-9}\) में हर ((x-3)(x+3)) है, इसलिए \(x=\pm3\) हटते हैं। परीक्षा में rational function में denominator zero values हटाएं।

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Mathematics Answer, Explanation and Revision Hints

किस फलन का डोमेन \(\mathbb{R}\setminus{-3,3}\) है? / Which function has domain \(\mathbb{R}\setminus{-3,3}\)?

Correct Answer: A. (f(x)=\frac{x}{x-2-9}). Explanation: \(\frac{x}{x^2-9}\) में हर ((x-3)(x+3)) है, इसलिए \(x=\pm3\) हटते हैं। परीक्षा में rational function में denominator zero values हटाएं। / In \(\frac{x}{x^2-9}\), the denominator is ((x-3)(x+3)), so \(x=\pm3\) are removed. In exams remove denominator zero values in rational functions.

Which concept should I revise for this Mathematics MCQ?

In \(\frac{x}{x^2-9}\), the denominator is ((x-3)(x+3)), so \(x=\pm3\) are removed. In exams remove denominator zero values in rational functions.

What exam hint can help solve this Mathematics question?

\(\frac{x}{x^2-9}\) में हर ((x-3)(x+3)) है, इसलिए \(x=\pm3\) हटते हैं। परीक्षा में rational function में denominator zero values हटाएं।