फलन (f(x)=\frac{1}{x-5}+2) का ऊर्ध्व आसिम्प्टोट कौन सा है?

What is the vertical asymptote of (f(x)=\frac{1}{x-5}+2)?

Explanation opens after your attempt
Correct Answer

A. (x=5)

Step 1

Concept

The denominator (x-5) cannot be zero. Therefore the vertical asymptote is (x=5).

Step 2

Why this answer is correct

The correct answer is A. (x=5). The denominator (x-5) cannot be zero. Therefore the vertical asymptote is (x=5).

Step 3

Exam Tip

हर (x-5) शून्य नहीं हो सकता। इसलिए ऊर्ध्व आसिम्प्टोट (x=5) है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{1}{x-5}+2) का ऊर्ध्व आसिम्प्टोट कौन सा है? / What is the vertical asymptote of (f(x)=\frac{1}{x-5}+2)?

Correct Answer: A. (x=5). Explanation: हर (x-5) शून्य नहीं हो सकता। इसलिए ऊर्ध्व आसिम्प्टोट (x=5) है। / The denominator (x-5) cannot be zero. Therefore the vertical asymptote is (x=5).

Which concept should I revise for this Mathematics MCQ?

The denominator (x-5) cannot be zero. Therefore the vertical asymptote is (x=5).

What exam hint can help solve this Mathematics question?

हर (x-5) शून्य नहीं हो सकता। इसलिए ऊर्ध्व आसिम्प्टोट (x=5) है।