द्वि-असमीका \(1<\frac{x-2}{3}\le 4\) का समाधान समुच्चय क्या है?

What is the solution set of the compound inequality \(1<\frac{x-2}{3}\le 4\)?

Explanation opens after your attempt
Correct Answer

A. \(5<x\le 14\)

Step 1

Concept

\(3<x-2\le 12\) gives \(5<x\le 14\). Carry open and closed signs correctly throughout.

Step 2

Why this answer is correct

The correct answer is A. \(5<x\le 14\). \(3<x-2\le 12\) gives \(5<x\le 14\). Carry open and closed signs correctly throughout.

Step 3

Exam Tip

\(3<x-2\le 12\) से \(5<x\le 14\)। परीक्षा में खुले और बंद चिन्हों को वैसा ही आगे बढ़ाएं।

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Mathematics Answer, Explanation and Revision Hints

द्वि-असमीका \(1<\frac{x-2}{3}\le 4\) का समाधान समुच्चय क्या है? / What is the solution set of the compound inequality \(1<\frac{x-2}{3}\le 4\)?

Correct Answer: A. \(5<x\le 14\). Explanation: \(3<x-2\le 12\) से \(5<x\le 14\)। परीक्षा में खुले और बंद चिन्हों को वैसा ही आगे बढ़ाएं। / \(3<x-2\le 12\) gives \(5<x\le 14\). Carry open and closed signs correctly throughout.

Which concept should I revise for this Mathematics MCQ?

\(3<x-2\le 12\) gives \(5<x\le 14\). Carry open and closed signs correctly throughout.

What exam hint can help solve this Mathematics question?

\(3<x-2\le 12\) से \(5<x\le 14\)। परीक्षा में खुले और बंद चिन्हों को वैसा ही आगे बढ़ाएं।