द्वि-असमीका \(1<\frac{x-2}{3}\le 4\) का समाधान समुच्चय क्या है?
What is the solution set of the compound inequality \(1<\frac{x-2}{3}\le 4\)?
Explanation opens after your attempt
A. \(5<x\le 14\)
Concept
\(3<x-2\le 12\) gives \(5<x\le 14\). Carry open and closed signs correctly throughout.
Why this answer is correct
The correct answer is A. \(5<x\le 14\). \(3<x-2\le 12\) gives \(5<x\le 14\). Carry open and closed signs correctly throughout.
Exam Tip
\(3<x-2\le 12\) से \(5<x\le 14\)। परीक्षा में खुले और बंद चिन्हों को वैसा ही आगे बढ़ाएं।
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