युग्म असमानता \(-7<\frac{x+2}{3}\le 1\) का हल समुच्चय क्या है?

What is the solution set of \(-7<\frac{x+2}{3}\le 1\)?

Explanation opens after your attempt
Correct Answer

C. \(-23<x\le 1\)

Step 1

Concept

Multiplying by (3) gives \(-21<x+2\le 3\). Therefore \(-23<x\le 1\) is the solution.

Step 2

Why this answer is correct

The correct answer is C. \(-23<x\le 1\). Multiplying by (3) gives \(-21<x+2\le 3\). Therefore \(-23<x\le 1\) is the solution.

Step 3

Exam Tip

(3) से गुणा करने पर \(-21<x+2\le 3\) मिलता है। इसलिए \(-23<x\le 1\) हल है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

युग्म असमानता \(-7<\frac{x+2}{3}\le 1\) का हल समुच्चय क्या है? / What is the solution set of \(-7<\frac{x+2}{3}\le 1\)?

Correct Answer: C. \(-23<x\le 1\). Explanation: (3) से गुणा करने पर \(-21<x+2\le 3\) मिलता है। इसलिए \(-23<x\le 1\) हल है। / Multiplying by (3) gives \(-21<x+2\le 3\). Therefore \(-23<x\le 1\) is the solution.

Which concept should I revise for this Mathematics MCQ?

Multiplying by (3) gives \(-21<x+2\le 3\). Therefore \(-23<x\le 1\) is the solution.

What exam hint can help solve this Mathematics question?

(3) से गुणा करने पर \(-21<x+2\le 3\) मिलता है। इसलिए \(-23<x\le 1\) हल है।