असमानता \(\frac{x-3}{2}\ge 4\) का हल कौन सा है?
What is the solution of \(\frac{x-3}{2}\ge 4\)?
Explanation opens after your attempt
Correct Answer
A. \(x\ge 11\)
Concept
Multiplying both sides by positive (2) gives \(x-3\ge 8\), so \(x\ge 11\). A positive denominator does not change the sign.
Why this answer is correct
The correct answer is A. \(x\ge 11\). Multiplying both sides by positive (2) gives \(x-3\ge 8\), so \(x\ge 11\). A positive denominator does not change the sign.
Exam Tip
दोनों पक्षों को धनात्मक (2) से गुणा करने पर \(x-3\ge 8\), अतः \(x\ge 11\) मिलता है। धनात्मक हर चिन्ह नहीं बदलता।
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