असमानता \(x+9\geq 2\) का अंतराल रूप क्या है?
What is the interval form of \(x+9\geq 2\)?
Explanation opens after your attempt
Correct Answer
A. \([-7,\infty\))
Concept
We get \(x\geq -7\), so the interval is \([-7,\infty\)). With equality, the left endpoint is closed.
Why this answer is correct
The correct answer is A. \([-7,\infty\)). We get \(x\geq -7\), so the interval is \([-7,\infty\)). With equality, the left endpoint is closed.
Exam Tip
\(x\geq -7\) मिलता है इसलिए अंतराल \([-7,\infty\)) होगा। बराबरी होने पर बायां सिरा बंद रहेगा।
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