फलन (f(x)=\sqrt{x-2-16}) का डोमेन क्या है?
What is the domain of (f(x)=\sqrt{x-2-16})?
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-4]\cup[4,\infty\))
Concept
The square root needs \(x^2-16\ge 0\), that is \(x^2\ge 16\). In exams \(x^2\ge a^2\) gives the outer intervals.
Why this answer is correct
The correct answer is A. (\(-\infty,-4]\cup[4,\infty\)). The square root needs \(x^2-16\ge 0\), that is \(x^2\ge 16\). In exams \(x^2\ge a^2\) gives the outer intervals.
Exam Tip
वर्गमूल के लिए \(x^2-16\ge 0\), यानी \(x^2\ge 16\)। परीक्षा में \(x^2\ge a^2\) से बाहरी अंतराल मिलते हैं।
Login to save your score, XP, coins and progress.