फलन (f(x)=\sqrt{(x+1)(x-5)}) का डोमेन क्या है?
What is the domain of (f(x)=\sqrt{(x+1)(x-5)})?
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-1]\cup[5,\infty\))
Concept
The expression inside the square root must satisfy ((x+1)(x-5)\ge0). A sign table gives the correct outer intervals.
Why this answer is correct
The correct answer is A. (\(-\infty,-1]\cup[5,\infty\)). The expression inside the square root must satisfy ((x+1)(x-5)\ge0). A sign table gives the correct outer intervals.
Exam Tip
वर्गमूल के अंदर ((x+1)(x-5)\ge0) होना चाहिए। संकेत तालिका से बाहरी अंतराल सही मिलते हैं।
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