फलन (f(x)=\sqrt{\frac{x-1}{x-7}}) का डोमेन क्या है?

What is the domain of (f(x)=\sqrt{\frac{x-1}{x-7}})?

Explanation opens after your attempt
Correct Answer

A. ((-\infty,1]\cup\(7,\infty\))

Step 1

Concept

The expression inside the square root must satisfy \(\frac{x-1}{x-7}\ge0\) and \(x\ne7\). A sign table gives ((-\infty,1]\cup\(7,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. ((-\infty,1]\cup\(7,\infty\)). The expression inside the square root must satisfy \(\frac{x-1}{x-7}\ge0\) and \(x\ne7\). A sign table gives ((-\infty,1]\cup\(7,\infty\)).

Step 3

Exam Tip

वर्गमूल के अंदर \(\frac{x-1}{x-7}\ge0\) और \(x\ne7\) चाहिए। संकेत तालिका से ((-\infty,1]\cup\(7,\infty\)) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{\frac{x-1}{x-7}}) का डोमेन क्या है? / What is the domain of (f(x)=\sqrt{\frac{x-1}{x-7}})?

Correct Answer: A. ((-\infty,1]\cup\(7,\infty\)). Explanation: वर्गमूल के अंदर \(\frac{x-1}{x-7}\ge0\) और \(x\ne7\) चाहिए। संकेत तालिका से ((-\infty,1]\cup\(7,\infty\)) मिलता है। / The expression inside the square root must satisfy \(\frac{x-1}{x-7}\ge0\) and \(x\ne7\). A sign table gives ((-\infty,1]\cup\(7,\infty\)).

Which concept should I revise for this Mathematics MCQ?

The expression inside the square root must satisfy \(\frac{x-1}{x-7}\ge0\) and \(x\ne7\). A sign table gives ((-\infty,1]\cup\(7,\infty\)).

What exam hint can help solve this Mathematics question?

वर्गमूल के अंदर \(\frac{x-1}{x-7}\ge0\) और \(x\ne7\) चाहिए। संकेत तालिका से ((-\infty,1]\cup\(7,\infty\)) मिलता है।