फलन (f(x)=\sqrt{\frac{6-x}{x+2}}) का डोमेन क्या है?

What is the domain of (f(x)=\sqrt{\frac{6-x}{x+2}})?

Explanation opens after your attempt
Correct Answer

A. ((-2,6])

Step 1

Concept

The expression inside the square root must satisfy \(\frac{6-x}{x+2}\ge0\) and \(x\ne-2\). A sign table gives ((-2,6]).

Step 2

Why this answer is correct

The correct answer is A. ((-2,6]). The expression inside the square root must satisfy \(\frac{6-x}{x+2}\ge0\) and \(x\ne-2\). A sign table gives ((-2,6]).

Step 3

Exam Tip

वर्गमूल के अंदर \(\frac{6-x}{x+2}\ge0\) और \(x\ne-2\) चाहिए। संकेत तालिका से ((-2,6]) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\sqrt{\frac{6-x}{x+2}}) का डोमेन क्या है? / What is the domain of (f(x)=\sqrt{\frac{6-x}{x+2}})?

Correct Answer: A. ((-2,6]). Explanation: वर्गमूल के अंदर \(\frac{6-x}{x+2}\ge0\) और \(x\ne-2\) चाहिए। संकेत तालिका से ((-2,6]) मिलता है। / The expression inside the square root must satisfy \(\frac{6-x}{x+2}\ge0\) and \(x\ne-2\). A sign table gives ((-2,6]).

Which concept should I revise for this Mathematics MCQ?

The expression inside the square root must satisfy \(\frac{6-x}{x+2}\ge0\) and \(x\ne-2\). A sign table gives ((-2,6]).

What exam hint can help solve this Mathematics question?

वर्गमूल के अंदर \(\frac{6-x}{x+2}\ge0\) और \(x\ne-2\) चाहिए। संकेत तालिका से ((-2,6]) मिलता है।