फलन (f(x)=\sqrt{\frac{6-x}{x+2}}) का डोमेन क्या है?
What is the domain of (f(x)=\sqrt{\frac{6-x}{x+2}})?
Explanation opens after your attempt
A. ((-2,6])
Concept
The expression inside the square root must satisfy \(\frac{6-x}{x+2}\ge0\) and \(x\ne-2\). A sign table gives ((-2,6]).
Why this answer is correct
The correct answer is A. ((-2,6]). The expression inside the square root must satisfy \(\frac{6-x}{x+2}\ge0\) and \(x\ne-2\). A sign table gives ((-2,6]).
Exam Tip
वर्गमूल के अंदर \(\frac{6-x}{x+2}\ge0\) और \(x\ne-2\) चाहिए। संकेत तालिका से ((-2,6]) मिलता है।
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