फलन (f(x)=\frac{1}{x-2+6x+10}) का डोमेन क्या है?

What is the domain of (f(x)=\frac{1}{x-2+6x+10})?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}\)

Step 1

Concept

The denominator (x-2+6x+10=(x+3)2+1) is never (0). In exams complete the square to test the denominator.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}\). The denominator (x-2+6x+10=(x+3)2+1) is never (0). In exams complete the square to test the denominator.

Step 3

Exam Tip

हर (x-2+6x+10=(x+3)2+1) कभी (0) नहीं होता। परीक्षा में पूर्ण वर्ग बनाकर हर की जांच करें।

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फलन (f(x)=\frac{1}{x-2+6x+10}) का डोमेन क्या है? / What is the domain of (f(x)=\frac{1}{x-2+6x+10})?

Correct Answer: A. \(\mathbb{R}\). Explanation: हर (x-2+6x+10=(x+3)2+1) कभी (0) नहीं होता। परीक्षा में पूर्ण वर्ग बनाकर हर की जांच करें। / The denominator (x-2+6x+10=(x+3)2+1) is never (0). In exams complete the square to test the denominator.

Which concept should I revise for this Mathematics MCQ?

The denominator (x-2+6x+10=(x+3)2+1) is never (0). In exams complete the square to test the denominator.

What exam hint can help solve this Mathematics question?

हर (x-2+6x+10=(x+3)2+1) कभी (0) नहीं होता। परीक्षा में पूर्ण वर्ग बनाकर हर की जांच करें।