असमानता \(\frac{x+5}{2}+\frac{x-1}{4}\geq 6\) का सही हल क्या है?
What is the correct solution of \(\frac{x+5}{2}+\frac{x-1}{4}\geq 6\)?
Explanation opens after your attempt
A. \(x\geq 5\)
Concept
Multiplying by (4) gives \(2x+10+x-1\geq 24\). Thus \(3x\geq 15\) and \(x\geq 5\).
Why this answer is correct
The correct answer is A. \(x\geq 5\). Multiplying by (4) gives \(2x+10+x-1\geq 24\). Thus \(3x\geq 15\) and \(x\geq 5\).
Exam Tip
(4) से गुणा करने पर \(2x+10+x-1\geq 24\) मिलता है। इसलिए \(3x\geq 15\) और \(x\geq 5\) है।
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