असमानताओं \(x\ge 0\), \(y\ge 0\), \(x\le 4\), \(y\le 3\) से बने क्षेत्र का क्षेत्रफल क्या होगा?

What is the area of the region formed by \(x\ge 0\), \(y\ge 0\), \(x\le 4\), and \(y\le 3\)?

Explanation opens after your attempt
Correct Answer

C. (12) वर्ग इकाई(12) square units

Step 1

Concept

The region is a rectangle of width (4) and height (3). Hence the area is \(4\times 3=12\).

Step 2

Why this answer is correct

The correct answer is C. (12) वर्ग इकाई / (12) square units. The region is a rectangle of width (4) and height (3). Hence the area is \(4\times 3=12\).

Step 3

Exam Tip

क्षेत्र (4) चौड़ाई और (3) ऊंचाई वाला आयत है। इसलिए क्षेत्रफल \(4\times 3=12\) है।

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Mathematics Answer, Explanation and Revision Hints

असमानताओं \(x\ge 0\), \(y\ge 0\), \(x\le 4\), \(y\le 3\) से बने क्षेत्र का क्षेत्रफल क्या होगा? / What is the area of the region formed by \(x\ge 0\), \(y\ge 0\), \(x\le 4\), and \(y\le 3\)?

Correct Answer: C. (12) वर्ग इकाई / (12) square units. Explanation: क्षेत्र (4) चौड़ाई और (3) ऊंचाई वाला आयत है। इसलिए क्षेत्रफल \(4\times 3=12\) है। / The region is a rectangle of width (4) and height (3). Hence the area is \(4\times 3=12\).

Which concept should I revise for this Mathematics MCQ?

The region is a rectangle of width (4) and height (3). Hence the area is \(4\times 3=12\).

What exam hint can help solve this Mathematics question?

क्षेत्र (4) चौड़ाई और (3) ऊंचाई वाला आयत है। इसलिए क्षेत्रफल \(4\times 3=12\) है।