संबंध \(R=\{(x,y):x^2+y^2=9,\ x\in{-3,0,3},\ y\in{-3,0,3}\}\) को (X) से (Y) में माना गया है। यह फलन क्यों नहीं है?
The relation \(R=\{(x,y):x^2+y^2=9,\ x\in{-3,0,3},\ y\in{-3,0,3}\}\) is considered from (X) to (Y). Why is it not a function?
Explanation opens after your attempt
Correct Answer
A. क्योंकि (x=0) की दो छवियां हैंBecause (x=0) has two images
Concept
At (x=0), both (y=3) and (y=-3) are possible. In a circular relation, one (x) may give two (y)-values.
Why this answer is correct
The correct answer is A. क्योंकि (x=0) की दो छवियां हैं / Because (x=0) has two images. At (x=0), both (y=3) and (y=-3) are possible. In a circular relation, one (x) may give two (y)-values.
Exam Tip
(x=0) पर (y=3) और (y=-3) दोनों संभव हैं। वृत्तीय संबंध में एक ही (x) के लिए दो (y) आ सकते हैं।
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