द्वि-असमीका \(-4<\frac{x+2}{2}\le 1\) को हल कीजिए।
Solve the compound inequality \(-4<\frac{x+2}{2}\le 1\).
Explanation opens after your attempt
Correct Answer
B. \(-10<x\le 0\)
Concept
Multiplying first by (2) gives \(-8<x+2\le 2\), so \(-10<x\le 0\). A positive multiplier does not change the inequality sign.
Why this answer is correct
The correct answer is B. \(-10<x\le 0\). Multiplying first by (2) gives \(-8<x+2\le 2\), so \(-10<x\le 0\). A positive multiplier does not change the inequality sign.
Exam Tip
पहले (2) से गुणा करने पर \(-8<x+2\le 2\), इसलिए \(-10<x\le 0\)। परीक्षा में धनात्मक गुणा से असमीका का चिन्ह नहीं बदलता।
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