द्वि-असमीका \(-2\le \frac{3x+1}{5}<4\) को हल कीजिए।
Solve the compound inequality \(-2\le \frac{3x+1}{5}<4\).
Explanation opens after your attempt
Correct Answer
B. \(-\frac{11}{3}\le x<\frac{19}{3}\)
Concept
Multiplying by (5) gives \(-10\le 3x+1<20\), so \(-\frac{11}{3}\le x<\frac{19}{3}\). A positive multiplier does not change the signs.
Why this answer is correct
The correct answer is B. \(-\frac{11}{3}\le x<\frac{19}{3}\). Multiplying by (5) gives \(-10\le 3x+1<20\), so \(-\frac{11}{3}\le x<\frac{19}{3}\). A positive multiplier does not change the signs.
Exam Tip
पहले (5) से गुणा करके \(-10\le 3x+1<20\) मिलता है, इसलिए \(-\frac{11}{3}\le x<\frac{19}{3}\)। परीक्षा में धनात्मक गुणा से चिन्ह नहीं बदलता।
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