प्रथम चतुर्थांश में \(x+4y\le 20\) और \(3x+y\le 18\) की सीमाओं का कटान कौन-सा है?

In the first quadrant, what is the intersection of the boundaries \(x+4y\le 20\) and \(3x+y\le 18\)?

Explanation opens after your attempt
Correct Answer

B. (\left\(\frac{52}{11},\frac{42}{11}\right\))

Step 1

Concept

Solving (x+4y=20) and (3x+y=18) gives (\left\(\frac{52}{11},\frac{42}{11}\right\)). Do not avoid fractions when finding exact vertices.

Step 2

Why this answer is correct

The correct answer is B. (\left\(\frac{52}{11},\frac{42}{11}\right\)). Solving (x+4y=20) and (3x+y=18) gives (\left\(\frac{52}{11},\frac{42}{11}\right\)). Do not avoid fractions when finding exact vertices.

Step 3

Exam Tip

(x+4y=20) और (3x+y=18) हल करने पर (\left\(\frac{52}{11},\frac{42}{11}\right\)) मिलता है। सटीक शीर्ष के लिए भिन्नों से डरें नहीं।

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प्रथम चतुर्थांश में \(x+4y\le 20\) और \(3x+y\le 18\) की सीमाओं का कटान कौन-सा है? / In the first quadrant, what is the intersection of the boundaries \(x+4y\le 20\) and \(3x+y\le 18\)?

Correct Answer: B. (\left\(\frac{52}{11},\frac{42}{11}\right\)). Explanation: (x+4y=20) और (3x+y=18) हल करने पर (\left\(\frac{52}{11},\frac{42}{11}\right\)) मिलता है। सटीक शीर्ष के लिए भिन्नों से डरें नहीं। / Solving (x+4y=20) and (3x+y=18) gives (\left\(\frac{52}{11},\frac{42}{11}\right\)). Do not avoid fractions when finding exact vertices.

Which concept should I revise for this Mathematics MCQ?

Solving (x+4y=20) and (3x+y=18) gives (\left\(\frac{52}{11},\frac{42}{11}\right\)). Do not avoid fractions when finding exact vertices.

What exam hint can help solve this Mathematics question?

(x+4y=20) और (3x+y=18) हल करने पर (\left\(\frac{52}{11},\frac{42}{11}\right\)) मिलता है। सटीक शीर्ष के लिए भिन्नों से डरें नहीं।