प्रथम चतुर्थांश में असमानताओं \(x+2y\le 16\), \(2x+y\le 14\), \(x\ge 0\), \(y\ge 0\) से बने हल क्षेत्र में दोनों तिरछी सीमाओं का साझा शीर्ष कौन-सा है?
In the first quadrant, what is the common vertex of the two slant boundaries in the solution region of \(x+2y\le 16\), \(2x+y\le 14\), \(x\ge 0\), \(y\ge 0\)?
Explanation opens after your attempt
D. (\left\(\frac{22}{3},\frac{13}{3}\right\))
Concept
Solving (x+2y=16) and (2x+y=14) together gives (\left\(\frac{22}{3},\frac{13}{3}\right\)). In a graph, always check key vertices from boundary intersections.
Why this answer is correct
The correct answer is D. (\left\(\frac{22}{3},\frac{13}{3}\right\)). Solving (x+2y=16) and (2x+y=14) together gives (\left\(\frac{22}{3},\frac{13}{3}\right\)). In a graph, always check key vertices from boundary intersections.
Exam Tip
रेखाओं (x+2y=16) और (2x+y=14) को साथ हल करने पर (\left\(\frac{22}{3},\frac{13}{3}\right\)) मिलता है। ग्राफ में मुख्य शीर्ष हमेशा सीमा रेखाओं के प्रतिच्छेद से जांचें।
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