यदि \(x\in \mathbb{Z}\) और \(-5\leq 2x-1<9\), तो कुल कितने पूर्णांक हल हैं?
If \(x\in \mathbb{Z}\) and \(-5\leq 2x-1<9\), how many integer solutions are there?
Explanation opens after your attempt
C. (7)
Concept
\(-4\leq 2x<10\) gives \(-2\leq x<5\), so (-2,-1,0,1,2,3,4) are (7) solutions. Check endpoints separately.
Why this answer is correct
The correct answer is C. (7). \(-4\leq 2x<10\) gives \(-2\leq x<5\), so (-2,-1,0,1,2,3,4) are (7) solutions. Check endpoints separately.
Exam Tip
\(-4\leq 2x<10\) से \(-2\leq x<5\) है इसलिए (-2,-1,0,1,2,3,4) कुल (7) हल हैं। सीमा बिंदुओं को अलग से जांचें।
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