यदि \(x\in \mathbb{Z}\) और \(-5\leq 2x-1<9\), तो कुल कितने पूर्णांक हल हैं?

If \(x\in \mathbb{Z}\) and \(-5\leq 2x-1<9\), how many integer solutions are there?

Explanation opens after your attempt
Correct Answer

C. (7)

Step 1

Concept

\(-4\leq 2x<10\) gives \(-2\leq x<5\), so (-2,-1,0,1,2,3,4) are (7) solutions. Check endpoints separately.

Step 2

Why this answer is correct

The correct answer is C. (7). \(-4\leq 2x<10\) gives \(-2\leq x<5\), so (-2,-1,0,1,2,3,4) are (7) solutions. Check endpoints separately.

Step 3

Exam Tip

\(-4\leq 2x<10\) से \(-2\leq x<5\) है इसलिए (-2,-1,0,1,2,3,4) कुल (7) हल हैं। सीमा बिंदुओं को अलग से जांचें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x\in \mathbb{Z}\) और \(-5\leq 2x-1<9\), तो कुल कितने पूर्णांक हल हैं? / If \(x\in \mathbb{Z}\) and \(-5\leq 2x-1<9\), how many integer solutions are there?

Correct Answer: C. (7). Explanation: \(-4\leq 2x<10\) से \(-2\leq x<5\) है इसलिए (-2,-1,0,1,2,3,4) कुल (7) हल हैं। सीमा बिंदुओं को अलग से जांचें। / \(-4\leq 2x<10\) gives \(-2\leq x<5\), so (-2,-1,0,1,2,3,4) are (7) solutions. Check endpoints separately.

Which concept should I revise for this Mathematics MCQ?

\(-4\leq 2x<10\) gives \(-2\leq x<5\), so (-2,-1,0,1,2,3,4) are (7) solutions. Check endpoints separately.

What exam hint can help solve this Mathematics question?

\(-4\leq 2x<10\) से \(-2\leq x<5\) है इसलिए (-2,-1,0,1,2,3,4) कुल (7) हल हैं। सीमा बिंदुओं को अलग से जांचें।