\(x_1+x_2+x_3+x_4=25\) और \(x_i\geq2\) हो, तो solutions की संख्या कौन-सी है?

If \(x_1+x_2+x_3+x_4=25\) and \(x_i\geq2\), what is the number of solutions?

Explanation opens after your attempt
Correct Answer

B. \(^{20}C_3\)

Step 1

Concept

Give (2) first to the four variables, leaving (17). In exams subtract the lower bound and apply non-negative stars and bars.

Step 2

Why this answer is correct

The correct answer is B. \(^{20}C_3\). Give (2) first to the four variables, leaving (17). In exams subtract the lower bound and apply non-negative stars and bars.

Step 3

Exam Tip

चार variables को पहले (2) देने पर (17) बचता है। परीक्षा में lower bound घटाकर non-negative stars and bars लगाएं।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

\(x_1+x_2+x_3+x_4=25\) और \(x_i\geq2\) हो, तो solutions की संख्या कौन-सी है? / If \(x_1+x_2+x_3+x_4=25\) and \(x_i\geq2\), what is the number of solutions?

Correct Answer: B. \(^{20}C_3\). Explanation: चार variables को पहले (2) देने पर (17) बचता है। परीक्षा में lower bound घटाकर non-negative stars and bars लगाएं। / Give (2) first to the four variables, leaving (17). In exams subtract the lower bound and apply non-negative stars and bars.

Which concept should I revise for this Mathematics MCQ?

Give (2) first to the four variables, leaving (17). In exams subtract the lower bound and apply non-negative stars and bars.

What exam hint can help solve this Mathematics question?

चार variables को पहले (2) देने पर (17) बचता है। परीक्षा में lower bound घटाकर non-negative stars and bars लगाएं।